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  • What is a bijective mapping?

    A bijective mapping is a function between two sets that is both injective and surjective. In other words, every element in the domain is paired with a unique element in the codomain, and every element in the codomain is paired with at least one element in the domain. This means that there is a one-to-one correspondence between the elements of the two sets. Bijective mappings are also known as one-to-one and onto functions.

  • How do I find a bijective mapping?

    To find a bijective mapping, you need to find a function that is both injective (one-to-one) and surjective (onto). This means that the function must map each element in the domain to a unique element in the codomain, and that every element in the codomain must be mapped to by at least one element in the domain. One way to find a bijective mapping is to first establish a one-to-one correspondence between the elements of the domain and the codomain, and then verify that the function is onto as well. Another approach is to start with a function and then prove that it is both injective and surjective.

  • How do you show that a mapping is bijective?

    To show that a mapping is bijective, you need to demonstrate that it is both injective and surjective. To show injectivity, you need to prove that distinct elements in the domain map to distinct elements in the codomain. This can be done by assuming two distinct elements in the domain map to the same element in the codomain and arriving at a contradiction. To show surjectivity, you need to prove that every element in the codomain has a preimage in the domain. This can be done by showing that for every element in the codomain, there exists an element in the domain that maps to it. If a mapping is both injective and surjective, it is bijective.

  • How can one show that a mapping is bijective?

    To show that a mapping is bijective, one must demonstrate that the mapping is both injective and surjective. Injectivity means that each element in the domain maps to a unique element in the codomain, while surjectivity means that every element in the codomain is mapped to by at least one element in the domain. If a mapping satisfies both conditions, it is bijective. One can prove injectivity by showing that distinct elements in the domain map to distinct elements in the codomain, and surjectivity by demonstrating that every element in the codomain is mapped to by at least one element in the domain.

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  • Is the mapping of the harmonic sum injective, surjective, or bijective?

    The mapping of the harmonic sum is not injective because different input values can result in the same output value. For example, both 2 and 3 can result in a harmonic sum of 1.5. The mapping is also not surjective because not all real numbers can be obtained as a harmonic sum. Therefore, the mapping of the harmonic sum is not bijective.

  • Is the inverse function of a bijective function also bijective?

    Yes, the inverse function of a bijective function is also bijective. This is because a bijective function is both injective (one-to-one) and surjective (onto), meaning that each element in the domain maps to a unique element in the codomain and every element in the codomain is mapped to by an element in the domain. Therefore, the inverse function will also be injective and surjective, making it bijective as well.

  • If g and g^(-1) are bijective, is f also bijective?

    If g and g^(-1) are bijective, it means that g is a bijection and its inverse g^(-1) is also a bijection. In this case, if f is composed with g and g^(-1), then f is also bijective. This is because composing f with a bijection and its inverse will preserve the bijectivity of f. Therefore, if g and g^(-1) are bijective, then f will also be bijective.

  • Is there a bijective mapping between the sets {0, 1} and {0, 1}?

    Yes, there is a bijective mapping between the sets {0, 1} and {0, 1}. The mapping can be defined as f(0) = 1 and f(1) = 0. This mapping is both injective and surjective, meaning that each element in the domain is mapped to a unique element in the codomain, and every element in the codomain is mapped to by an element in the domain. Therefore, this mapping is bijective.

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